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(A) The initial nucleus $A$ has mass number $M = 180$ and atomic number $Z = 72$.$1$. Emission of an $\alpha$-particle $(_{2}^{4}He)$ reduces the mass

Vedclass · Accepted Answer

$172$ and $69$

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(A) The initial nucleus $A$ has mass number $M = 180$ and atomic number $Z = 72$.$1$. Emission of an $\alpha$-particle $(_{2}^{4}He)$ reduces the mass number by $4$ and the atomic number by $2$.$2$. Emission of a $\beta$-particle $(_{-1}^{0}e)$ does not change the mass number but increases the atomic number by $1$.$3$. Emission of a $\gamma$-ray does not change the mass number or the atomic number.Sequence of decays:$A(180, 72) \xrightarrow{\alpha} A_1(176, 70) \xrightarrow{\beta} A_2(176, 71) \xrightarrow{\alpha} A_3(172, 69) \xrightarrow{\gamma} A_4(172, 69)$.Therefore,the mass number and atomic number for $A_4$ are $172$ and $69$ respectively.

$A$ radioactive nucleus undergoes a series of decays according to the scheme
$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$
If the mass number and atomic number of $A$ are $180$ and $72$,respectively,then what are these numbers for $A_4$?

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$A$ radioactive nucleus undergoes a series of decays according to the scheme$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$If the mass number and atomic number of $A$ are $180$ and $72$,respectively,then what are these numbers for $A_4$?